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100x^2+2x=4.83
We move all terms to the left:
100x^2+2x-(4.83)=0
We add all the numbers together, and all the variables
100x^2+2x-4.83=0
a = 100; b = 2; c = -4.83;
Δ = b2-4ac
Δ = 22-4·100·(-4.83)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-44}{2*100}=\frac{-46}{200} =-23/100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+44}{2*100}=\frac{42}{200} =21/100 $
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